标签：
导读 steam社保大黄油∫(0->2π) | sin(x+1) | dx=∫(0->π-1) sin(x+1) dx - ∫(π-1-> 2π-1) sin(x+1) dx + ∫(2π-1-> 2π) ...
steam社保大黄油∫(0->2π) | sin(x+1) | dx=∫(0->π-1) sin(x+1) dx - ∫(π-1-> 2π-1) sin(x+1) dx + ∫(2π-1-> 2π) sin(x+1) dx= -[cos(x+1)]|(0->π-1) + [cos(x+1)]|(π-1-> 2π-1) - [cos(x+1)]|(2π-1->2π)=4 +2cos1。